Get the log of 8, base 2 : Log « Numerical Math Functions « Oracle PL/SQL Tutorial






SQL> -- create demo table
SQL> create table myTable(
  2    id           NUMBER(2),
  3    value        NUMBER(6,2)
  4  )
  5  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into myTable(ID,  value)values (1,9)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (2,2.11)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (3,3.44)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (4,-4.21)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (5,10)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (6,3)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (7,-5.88)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (8,123.45)
  2  /

1 row created.

SQL> insert into myTable(ID,  value)values (9,98.23)
  2  /

1 row created.

SQL>
SQL> select * from myTable
  2  /

        ID      VALUE
---------- ----------
         1          9
         2       2.11
         3       3.44
         4      -4.21
         5         10
         6          3
         7      -5.88
         8     123.45
         9      98.23

9 rows selected.

SQL>
SQL> SELECT LOG(2,8) FROM myTable
  2  /

  LOG(2,8)
----------
         3
         3
         3
         3
         3
         3
         3
         3
         3

9 rows selected.

SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
  2  /

Table dropped.

SQL>








14.14.Log
14.14.1.Log and Exponential Functions
14.14.2.Using the LOG function
14.14.3.Get the log of 8, base 2
14.14.4.LOG(2, 4)
14.14.5.LOG(2, 5)