Use TO_CHAR() to convert columns containing numbers to strings. : TO_CHAR « Conversion Functions « Oracle PL/SQL Tutorial






SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ('01','Jason',    'Martin',  to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto',  'Programmer')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('02','Alison',   'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('03','James',    'Smith',   to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('04','Celia',    'Rice',    to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('05','Robert',   'Black',   to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('06','Linda',    'Green',   to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York',  'Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('07','David',    'Larry',   to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York',  'Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('08','James',    'Cat',     to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')
  3  /

1 row created.

SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /

ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester

8 rows selected.

SQL>
SQL>
SQL> SELECT id, 'The salary of this employee is' || TO_CHAR(salary, '$99999999.99')
  2  FROM employee;

ID   'THESALARYOFTHISEMPLOYEEIS'||TO_CHAR(SALARY
---- -------------------------------------------
01   The salary of this employee is     $1234.56
02   The salary of this employee is     $6661.78
03   The salary of this employee is     $6544.78
04   The salary of this employee is     $2344.78
05   The salary of this employee is     $2334.78
06   The salary of this employee is     $4322.78
07   The salary of this employee is     $7897.78
08   The salary of this employee is     $1232.78

8 rows selected.

SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
  2  /

Table dropped.

SQL>








15.7.TO_CHAR
15.7.1.Format Parameters
15.7.2.TO_CHAR(x [, format]) converts x to a string.
15.7.3.TO_CHAR() will return a string of pound characters (#) if you try and format a number that contains too many digits for the format you have provided.
15.7.4.Use TO_CHAR() to convert columns containing numbers to strings.
15.7.5.TO_CHAR(12345.67, '99,999.99') (1)
15.7.6.TO_CHAR(12345.67, '99999.99') (2)
15.7.7.TO_CHAR(-12345.67, '99,999.99') (3)
15.7.8.TO_CHAR(12345.67, '099,999.99') (4)
15.7.9.TO_CHAR(12345.67, '99,999.9900')
15.7.10.TO_CHAR(12345.67, '$99,999.99')
15.7.11.TO_CHAR(0.67, 'B9.99')
15.7.12.TO_CHAR(12345.67, 'C99,999.99')
15.7.13.TO_CHAR(12345.67, '99999D99')
15.7.14.TO_CHAR(12345.67, '99999.99EEEE')
15.7.15.TO_CHAR(0012345.6700, 'FM99999.99')
15.7.16.TO_CHAR(12345.67, '99999G99')
15.7.17.TO_CHAR(12345.67, 'L99,999.99')
15.7.18.TO_CHAR(-12345.67, '99,999.99MI')
15.7.19.TO_CHAR(-12345.67, '99,999.99PR')
15.7.20.TO_CHAR(2007, 'RN')
15.7.21.TO_CHAR(12345.67, 'TM')
15.7.22.TO_CHAR(12345.67, 'U99,999.99')
15.7.23.TO_CHAR(12345.67, '99999V99')
15.7.24.TO_CHAR(last_ddl_time,'dd-mon-yyyy hh24:mi')
15.7.25.to_char(sysdate,'hh24:mi:ss') as time
15.7.26.to_char(to_date('01/01/2006','dd/mm/yyyy'),is on Day') as new_year_2006
15.7.27.to_char(sysdate, 'Day', 'nls_date_language=Dutch')
15.7.28.to_char(sysdate,'DAY dy Dy')
15.7.29.to_char(sysdate,'MONTH mon') as month
15.7.30.to_char(bdate,'fmMonth ddth, yyyy')
15.7.31.use to_char more than once to create long date format