Unbounded Following : UNBOUNDED « Analytical Functions « Oracle PL/SQL Tutorial






SQL>
SQL> -- create demo table
SQL> create table myTable(
  2    id           NUMBER(2),
  3    value        NUMBER(6,2)
  4  )
  5  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into myTable(ID,  value)values (1,9);

1 row created.

SQL> insert into myTable(ID,  value)values (2,2.11);

1 row created.

SQL> insert into myTable(ID,  value)values (3,3.44);

1 row created.

SQL> insert into myTable(ID,  value)values (4,-4.21);

1 row created.

SQL> insert into myTable(ID,  value)values (5,10);

1 row created.

SQL> insert into myTable(ID,  value)values (6,3);

1 row created.

SQL> insert into myTable(ID,  value)values (7,-5.88);

1 row created.

SQL> insert into myTable(ID,  value)values (8,123.45);

1 row created.

SQL> insert into myTable(ID,  value)values (9,98.23);

1 row created.

SQL> insert into myTable(ID,  value)values (10,938.23);

1 row created.

SQL> insert into myTable(ID,  value)values (11,984.23);

1 row created.

SQL> insert into myTable(ID,  value)values (12,198.23);

1 row created.

SQL> insert into myTable(ID,  value)values (13,928.87);

1 row created.

SQL> insert into myTable(ID,  value)values (14,25.37);

1 row created.

SQL> insert into myTable(ID,  value)values (15,918.3);

1 row created.

SQL> insert into myTable(ID,  value)values (16,9.23);

1 row created.

SQL> insert into myTable(ID,  value)values (17,8.23);

1 row created.

SQL>
SQL> select * from myTable
  2  /

        ID      VALUE
---------- ----------
         1          9
         2       2.11
         3       3.44
         4      -4.21
         5         10
         6          3
         7      -5.88
         8     123.45
         9      98.23
        10     938.23
        11     984.23

        ID      VALUE
---------- ----------
        12     198.23
        13     928.87
        14      25.37
        15      918.3
        16       9.23
        17       8.23

17 rows selected.

SQL>
SQL>
SQL> SELECT id "ID", value,
  2    SUM(value) OVER(ORDER BY id
  3      ROWS BETWEEN CURRENT ROW
  4      AND UNBOUNDED FOLLOWING) "Running total"
  5  FROM myTable
  6  ORDER BY id;

        ID      VALUE Running total
---------- ---------- -------------
         1          9      4,249.83
         2       2.11      4,240.83
         3       3.44      4,238.72
         4      -4.21      4,235.28
         5         10      4,239.49
         6          3      4,229.49
         7      -5.88      4,226.49
         8     123.45      4,232.37
         9      98.23      4,108.92
        10     938.23      4,010.69
        11     984.23      3,072.46

        ID      VALUE Running total
---------- ---------- -------------
        12     198.23      2,088.23
        13     928.87      1,890.00
        14      25.37        961.13
        15      918.3        935.76
        16       9.23         17.46
        17       8.23          8.23

17 rows selected.

SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
  2  /

Table dropped.

SQL>
SQL>








16.28.UNBOUNDED
16.28.1.Displaying a Running Total Using SUM as an Analytical Function
16.28.2.Unbounded Following