Sort in a for-each loop : Sort « XSLT stylesheet « XML Tutorial






File: Data.xml

<?xml version="1.0"?>
<numberlist>
  <number>127</number>
  <number>23</number>
  <number>10</number>
</numberlist>

File: Transform.xslt

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="text" indent="no"/>
  <xsl:strip-space elements="*"/>

  <xsl:variable name="newline">
  <xsl:text></xsl:text>
  </xsl:variable>

  <xsl:template match="/">
    <xsl:for-each select="numberlist/number">
      <xsl:sort select="." data-type="number"/>
      <xsl:value-of select="."/>
      <xsl:value-of select="$newline"/>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

Output:

1023127








5.18.Sort
5.18.1.The Element is used to specify sort order for node-sets
5.18.2.sort order="descending" select="."
5.18.3.sort elements
5.18.4.sort order="descending"
5.18.5.sort data-type="number" order="descending"
5.18.6.sort by name()
5.18.7.sort by attribute: sort select="@joined" data-type="number" order="descending"
5.18.8.Sort by different data types and order
5.18.9.Sort in a for-each loop
5.18.10.Sort by last name than first name
5.18.11.sort select="." data-type="number"
5.18.12.sort select="xs:integer(.)"
5.18.13.sort select="."