sort order="descending" : Sort « XSLT stylesheet « XML Tutorial






File: Data.xml

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet href="Transform.xslt" type="text/xsl"?>

<europe>
  <state>Belgium</state>
  <state>Germany</state>
  <state>Finland</state>
  <state>Greece</state>
  <state>Ireland</state>
  <state>Luxembourg</state>
  <state>Switzerland</state>
</europe>

File: Transform.xslt

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text" />

  <xsl:template match="europe">
    <xsl:apply-templates select="state">
      <xsl:sort order="descending" />
    </xsl:apply-templates>
    <xsl:text>Number of European States: </xsl:text>
    <xsl:value-of select="count(state)" />
    <xsl:text>&#10;</xsl:text>
  </xsl:template>

  <xsl:template match="state">
    <xsl:text> - </xsl:text>
    <xsl:apply-templates />
    <xsl:text>&#10;</xsl:text>
  </xsl:template>

</xsl:stylesheet>

Output:

 - Switzerland
 - Luxembourg
 - Ireland
 - Greece
 - Germany
 - Finland
 - Belgium
Number of European States: 7








5.18.Sort
5.18.1.The Element is used to specify sort order for node-sets
5.18.2.sort order="descending" select="."
5.18.3.sort elements
5.18.4.sort order="descending"
5.18.5.sort data-type="number" order="descending"
5.18.6.sort by name()
5.18.7.sort by attribute: sort select="@joined" data-type="number" order="descending"
5.18.8.Sort by different data types and order
5.18.9.Sort in a for-each loop
5.18.10.Sort by last name than first name
5.18.11.sort select="." data-type="number"
5.18.12.sort select="xs:integer(.)"
5.18.13.sort select="."