C# BigInteger Max
Description
BigInteger Max Returns the larger of two BigInteger values.
Syntax
BigInteger.Max has the following syntax.
public static BigInteger Max(
BigInteger left,
BigInteger right
)
Parameters
BigInteger.Max has the following parameters.
left- The first value to compare.right- The second value to compare.
Returns
BigInteger.Max method returns The left or right parameter, whichever is larger.
Example
using System;// w w w . j av a2 s .c o m
using System.Numerics;
public class Example
{
public static void Main()
{
BigInteger[] numbers = { Int64.MaxValue * BigInteger.MinusOne,
BigInteger.MinusOne,
10359321239000,
BigInteger.Pow(103988, 2),
BigInteger.Multiply(Int32.MaxValue, Int16.MaxValue),
BigInteger.Add(BigInteger.Pow(Int64.MaxValue, 2),
BigInteger.Pow(Int32.MaxValue, 2)) };
BigInteger largest = numbers[numbers.GetLowerBound(0)];
for (int ctr = numbers.GetLowerBound(0) + 1; ctr <= numbers.GetUpperBound(0); ctr++)
largest = BigInteger.Max(largest, numbers[ctr]);
Console.WriteLine(" {0:N0}", largest);
}
}
The code above generates the following result.
