C# BigInteger Min
Description
BigInteger Min Returns the smaller of two BigInteger
values.
Syntax
BigInteger.Min has the following syntax.
public static BigInteger Min(
BigInteger left,
BigInteger right
)
Parameters
BigInteger.Min has the following parameters.
left- The first value to compare.right- The second value to compare.
Returns
BigInteger.Min method returns The left or right parameter, whichever is smaller.
Example
using System;// ww w . ja v a 2 s . co m
using System.Numerics;
public class Example
{
public static void Main()
{
BigInteger[] numbers = { Int64.MaxValue * BigInteger.MinusOne,
BigInteger.MinusOne,
BigInteger.Add(BigInteger.Pow(Int64.MaxValue, 2),
BigInteger.Pow(Int32.MaxValue, 2)),
BigInteger.Zero };
BigInteger smallest = numbers[numbers.GetLowerBound(0)];
for (int ctr = numbers.GetLowerBound(0) + 1; ctr <= numbers.GetUpperBound(0); ctr++)
smallest = BigInteger.Min(smallest, numbers[ctr]);
Console.WriteLine(" {0:N0}", smallest);
}
}
The code above generates the following result.
