Finds how many years it takes for the value of compounded interest to exceed the value of simple interest. - C Operator

C examples for Operator:Arithmetic Operator

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Introduction

Tom invests $100 at 10% . Every year, the investment earns an interest equal to 10% of the original investment.

Jack invests $100 at 5% interest compounded annually. That is, interest is 5% of the current balance, including previous addition of interest.

Demo Code

#include <stdio.h>  
#define RATE_SIMP 0.10  //from ww  w.j  a v a2  s.  co m
#define RATE_COMP 0.05  
#define INIT_AMT 100.0  
int main( void )  
{  
    double tom = INIT_AMT;  
    double jack = INIT_AMT;  
    int years = 0;  
      
    while (jack <= tom)  
    {  
        tom += RATE_SIMP * INIT_AMT;  
        jack += RATE_COMP * jack;  
        ++years;  
    }  
    printf("Investment values after %d years:\n", years);  
    printf("tom: $%.2f\n", tom);  
    printf("jack: $%.2f\n", jack);  
    return 0;  
}

Result


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