Java Utililty Methods Array Divide

List of utility methods to do Array Divide

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Description

The list of methods to do Array Divide are organized into topic(s).

Method

double[]arrayDivide(double[] a, double[] b)
Divides two vectors of doubles, array-wise. 
double[] out = new double[a.length];
for (int i = 0; i < a.length; i++) {
    out[i] = a[i] / b[i];
return out;
double[]arrayDivide(double[] d1, double denominator)
Divides each element of an array by a number. 
if (d1 == null) {
    throw new IllegalArgumentException("Array cannot be null.");
double[] dDivide = new double[d1.length];
for (int i = 0; i < d1.length; i++) {
    dDivide[i] = d1[i] / denominator;
return dDivide;
...
double[]arrayDivision(double[] array, double number)
A quick method for simple array division in Java. 
double[] newArray = new double[array.length];
for (int i = 0; i < array.length; i++) {
    newArray[i] = array[i] / number;
return newArray;
double[]div(double a, double[] b)
div 
if (a == 0)
    throw new IllegalArgumentException("Divison by zero");
double[] erg = new double[b.length];
for (int i = 0; i < b.length; i++) {
    erg[i] = b[i] / a;
return erg;
int[]div(final int[] result, final int[] vector, final int[] scale)
Divides a vector by param using given result int[], result = vector / scale 
for (int i = 0; i < result.length; i++) {
    result[i] = vector[i] / scale[i];
return result;
float[]div(float[] items, int offset, int length, float divisor)
div 
return mul(items, offset, length, 1 / divisor);
float[]div(float[] items, int offset, int length, float divisorX, float divisorY)
div 
for (int i = offset; i < offset + length; i += 2) {
    items[i] /= divisorX;
    items[i + 1] /= divisorY;
return items;
float[]div(float[] nums, float n)
div 
assert !Float.isInfinite(n) : "Trying to divide " + Arrays.toString(nums) + " by  " + n; 
for (int i = 0; i < nums.length; i++)
    nums[i] /= n;
return nums;
float[]div(float[] nums, int n)
div 
for (int i = 0; i < nums.length; i++)
    nums[i] /= n;
return nums;
float[]div(float[] nums, int n)
div 
for (int i = 0; i < nums.length; i++)
    nums[i] /= n;
return nums;