Java Utililty Methods Array Normalize

List of utility methods to do Array Normalize

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Description

The list of methods to do Array Normalize are organized into topic(s).

Method

voidnormalize(double[] state)
Normalizes the quaternion. 
double norm = 1
        / Math.sqrt(state[0] * state[0] + state[2] * state[2] + state[4] * state[4] + state[6] * state[6]);
state[0] *= norm;
state[2] *= norm;
state[4] *= norm;
state[6] *= norm;
double[]normalize(double[] v)
Renormalizes the array so that its L2 norm is 1 (up to computational errors). 
return (scalarMultiply(1.0 / norm(v), v));
double[]normalize(double[] v)
returns vector v normalized 
double[] v0 = new double[3];
double n = norm(v);
v0[0] = v[0] / n;
v0[1] = v[1] / n;
v0[2] = v[2] / n;
return (v0);
voidnormalize(double[] vals)
normalize 
double total = 0.0;
for (int i = 0; i < vals.length; i++)
    total += vals[i];
for (int i = 0; i < vals.length; i++)
    vals[i] = vals[i] / total;
double[]normalize(double[] values)
Normalize to a distribution in which the sum of all the elements is 1 
double sum = sum(values);
double[] norm = new double[values.length];
for (int i = 0; i < norm.length; i++) {
    norm[i] = values[i] / sum;
return norm;
double[]normalize(double[] values)
normalize 
double sum = 0;
for (int i = 0; i < values.length; i++) {
    sum += (values[i] * values[i]);
sum = Math.sqrt(sum);
double[] newValues = new double[values.length];
for (int i = 0; i < newValues.length; i++) {
    newValues[i] = values[i] / sum;
...
double[]normalize(double[] vector)
normalize 
double magnitude = magnitude(vector);
return magnitude != 0 ? mult(vector, 1 / magnitude) : vector;
voidnormalize(double[] vector)
normalize 
double norm = getNorm(vector);
for (int i = 0; i < vector.length; i++) {
    vector[i] = vector[i] / norm;
double[]normalize(double[] w)
Normalize the values of the array 
double[] vector = w;
for (int i = 0; i < w.length; i++) {
    if (w[i] > 0.4)
        vector[i] -= .005;
    else if (w[i] < 0.4)
        vector[i] += .005;
    else
        vector[i] = 0.4;
...
double[]normalize(double[] weights)
Returns an array of doubles resulting from the normalization of a given array of (positive) doubles. 
double[] result = new double[weights.length];
double sum = sum(weights);
for (int i = 0; i != weights.length; i++)
    result[i] = weights[i] / sum;
return result;