Java ByteArrayOutputStream Write readAllBinary(InputStream stream)

Here you can find the source of readAllBinary(InputStream stream)

Description

fully reads a stream

License

Apache License

Exception

Parameter Description
IOException an exception

Return

a string with all the contents of the stream

Declaration

public static byte[] readAllBinary(InputStream stream) throws IOException 

Method Source Code

//package com.java2s;
/*// w w  w. j  a  va  2s  .co  m
Copyright 2008 Flaptor (flaptor.com) 
    
Licensed under the Apache License, Version 2.0 (the "License"); 
you may not use this file except in compliance with the License. 
You may obtain a copy of the License at 
    
http://www.apache.org/licenses/LICENSE-2.0 
    
Unless required by applicable law or agreed to in writing, software 
distributed under the License is distributed on an "AS IS" BASIS, 
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 
See the License for the specific language governing permissions and 
limitations under the License.
*/

import java.io.ByteArrayOutputStream;

import java.io.IOException;
import java.io.InputStream;

public class Main {
    /**
     * fully reads a stream
     * @return a string with all the contents of the stream 
     * @throws IOException 
     */
    public static byte[] readAllBinary(InputStream stream) throws IOException {
        ByteArrayOutputStream o = new ByteArrayOutputStream();
        byte[] buffer = new byte[256];
        while (true) {
            int bytesRead = stream.read(buffer);
            if (bytesRead == -1)
                break;
            o.write(buffer, 0, bytesRead);
        }
        return o.toByteArray();
    }
}

Related

  1. readAll(InputStream is)
  2. readAll(InputStream s)
  3. readAll(InputStream stream)
  4. readAllAndClose(InputStream is)
  5. readAllAndKeepOpen(InputStream bytes, int bufferSize)
  6. readAllFrom(InputStream in, boolean chunked)
  7. readAllFromFile(File f)
  8. readAllFromFile(String file)
  9. readAllTextFromResource(String resourceName)