Java Class Name Extract extractClassName(String fullyQualifiedClassName)

Here you can find the source of extractClassName(String fullyQualifiedClassName)

Description

Extracts class name from a fully qualified class name For example, when 'org.wso2.developerStudio.Test' is given as an argument, it will return 'Test'

License

Open Source License

Declaration

public static String extractClassName(String fullyQualifiedClassName) 

Method Source Code

//package com.java2s;
/*//from  w w w. ja v  a2 s  .co  m
 * Copyright (c) 2015, WSO2 Inc. (http://www.wso2.org) All Rights Reserved.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    private static final String DOT_SEPARATOR = ".";

    /**
     * Extracts class name from a fully qualified class name
     * For example, when 'org.wso2.developerStudio.Test' is given as an argument, it will return 'Test'
     */
    public static String extractClassName(String fullyQualifiedClassName) {
        int lastIndexOfDot = fullyQualifiedClassName.lastIndexOf(DOT_SEPARATOR);
        return fullyQualifiedClassName.substring(++lastIndexOfDot, fullyQualifiedClassName.length());
    }
}

Related

  1. extractClassName(final String classPath)
  2. extractClassName(final String fullClassName)
  3. extractClassName(String fullClassName)
  4. extractClassName(String fullElement)
  5. extractClassName(String javaSource)
  6. extractClassName(String methodName)
  7. extractClassName(String qualifiedName)
  8. extractClassNameFromArray(final String arrayName)