Java Class Name Get getClassNameWithoutPackage(Object object)

Description

get Class Name Without Package

License

Apache License

Declaration

public static String getClassNameWithoutPackage(Object object) 

Method Source Code

//package com.java2s;
/* Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * /*from  w  ww . ja v  a2 s.  c o m*/
 *      http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.HashMap;
import java.util.Map;

public class Main {
    protected static final Map<Class<?>, String> cachedNames = new HashMap<Class<?>, String>();

    public static String getClassNameWithoutPackage(Object object) {
        return getClassNameWithoutPackage(object.getClass());
    }

    public static String getClassNameWithoutPackage(Class<?> clazz) {
        String unqualifiedClassName = cachedNames.get(clazz);
        if (unqualifiedClassName == null) {
            String fullyQualifiedClassName = clazz.getName();
            unqualifiedClassName = fullyQualifiedClassName.substring(fullyQualifiedClassName.lastIndexOf('.') + 1);
            cachedNames.put(clazz, unqualifiedClassName);
        }
        return unqualifiedClassName;
    }
}

Related

1. getClassName(String upnpDataType)
2. getClassNameAsSrc(Class clazz)
3. getClassNameFromConfig(Object config)
4. getClassNames( StackTraceElement[] currentStack)
5. getClassNames(Class[] ifaces)