Java Utililty Methods Day in Month

return getDayOfYear(time) - getMonthOfYear(time) * daysInMonth;

Date date = new Date(Long.parseLong(millis.toString()));
String d = (new SimpleDateFormat("dd")).format(date);
return d;

String[] lParts = aDatetime.split("\\.", 0);
while (lParts[2].startsWith("0"))
    lParts[2] = lParts[2].substring(1);
return Integer.parseInt(lParts[2]);

return Integer.valueOf(dateKey.substring(6, 8));

return daySuffixes[day];

return String.format("%02d", value);

int day = 30;
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) {
    day = 31;
} else if (month == 2) {
    day = 28;
return day;

if (month == 0) {
    return 31;
} else if (month == 1) {
    if (isLeapYear(year)) {
        return 29;
    } else {
        return 28;
} else if (month == 2) {
    return 31;
} else if (month == 3) {
    return 30;
} else if (month == 4) {
    return 31;
} else if (month == 5) {
    return 30;
} else if (month == 6) {
    return 31;
} else if (month == 7) {
    return 31;
} else if (month == 8) {
    return 30;
} else if (month == 9) {
    return 31;
} else if (month == 10) {
    return 30;
} else if (month == 11) {
    return 31;
return -1;

int m = days_in_month[month - 1];
if (month == 2 && isLeapYear(year)) {
    m++;
return m;

if (monthNum < 0) {
    throw new IllegalArgumentException("Month number must be non-negative");
if (monthNum >= 12) {
    throw new IndexOutOfBoundsException("There are 12 months in a year, so monthNum must be in 0..11");
return DOM[monthNum];