Java Utililty Methods Day Of Year

List of utility methods to do Day Of Year

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Description

The list of methods to do Day Of Year are organized into topic(s).

Method

StringcurrentYearMonthDay()
current Year Month Day 
SimpleDateFormat sdf = new SimpleDateFormat("yyyy_MM_dd");
return sdf.format(new Date().getTime());
booleandateOfYearBetween(final int month, final int dayOfMonth, final int fromMonth, final int fromDayOfMonth, final int toMonth, final int toDayOfMonth)
date Of Year Between 
if (fromMonth == toMonth) {
    if (month != fromMonth) {
        return false;
    if (dayOfMonth < fromDayOfMonth || dayOfMonth > toDayOfMonth) {
        return false;
} else if (fromMonth < toMonth) {
...
intdayOfYear(final int year, final int month, final int day)
day Of Year 
int day_of_year;
if (isLeapYear(year)) {
    day_of_year = 275 * month / 9 - (month + 9) / 12 + day - 30;
} else {
    day_of_year = 275 * month / 9 - ((month + 9) / 12 << 1) + day - 30;
return day_of_year;
intdayOfYear(int month, int day, int year)
return the day of year for the month and day, for the given year 
return day + dayOffset[isLeapYear(year) ? 1 : 0][month];
intdayOfYear(int year, int month, int date)
the day of the year in [0-365] of the given date. 
int leapAdjust = month > 2 && isLeapYear(year) ? 1 : 0;
return MONTH_START_TO_DOY[month - 1] + leapAdjust + date - 1;
intdayOfYear(int year, int month, int day)
Gets day number in year 
int K = (isLeapYear(year)) ? 1 : 2;
int N = (int) ((int) ((275 * month) / 9) - K * (int) ((month + 9) / 12) + day - 30);
return N;
intdayOfYear(int year, int month, int day)
Day of year. 
return DAYS_OF_YEAR_PER_MONTH[month - 1] + day + (month >= 3 && isLeapYear(year) ? 1 : 0);
intdaysInPriorYears(final int y)
Return the number of days in the years from 0 AD to December 31th of the given year. 
return 365 * y 
        + y / 4 
        - y / 100 
        + y / 400;
intdaysInPriorYears(int yr)
Return the number of days in prior years since 1601 
if (yr < 1601) {
    throw new IllegalArgumentException("'year' must be 1601 or greater");
int y = yr - 1601;
int days = 365 * y 
        + y / 4 
        - y / 100 
        + y / 400; 
...
intdaysInPriorYears(int yr, boolean use1904windowing)
Return the number of days in prior years since 1900 
if ((!use1904windowing && yr < 1900) || (use1904windowing && yr < 1900)) {
    throw new IllegalArgumentException("'year' must be 1900 or greater");
int yr1 = yr - 1;
int leapDays = yr1 / 4 
        - yr1 / 100 
        + yr1 / 400 
        - 460; 
...