Here you can find the source of distance(float[] p1, float[] p2)
public static float distance(float[] p1, float[] p2)
//package com.java2s; /* /*from www. j a v a 2 s. c o m*/ * Copyright 2008-2013, ETH Z?rich, Samuel Welten, Michael Kuhn, Tobias Langner, * Sandro Affentranger, Lukas Bossard, Michael Grob, Rahul Jain, * Dominic Langenegger, Sonia Mayor Alonso, Roger Odermatt, Tobias Schlueter, * Yannick Stucki, Sebastian Wendland, Samuel Zehnder, Samuel Zihlmann, * Samuel Zweifel * * This file is part of Jukefox. * * Jukefox is free software: you can redistribute it and/or modify it under the * terms of the GNU General Public License as published by the Free Software * Foundation, either version 3 of the License, or any later version. Jukefox is * distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; * without even the implied warranty of MERCHANTABILITY or FITNESS FOR A * PARTICULAR PURPOSE. See the GNU General Public License for more details. * * You should have received a copy of the GNU General Public License along with * Jukefox. If not, see <http://www.gnu.org/licenses/>. */ public class Main { public static float distance(float[] p1, float[] p2) { return (float) Math.sqrt(squareDistance(p1, p2)); } public static float squareDistance(float[] p1, float[] p2) throws ArrayIndexOutOfBoundsException { if (p1.length != p2.length) { throw new ArrayIndexOutOfBoundsException(Math.max(p1.length, p2.length)); } float sum = 0; for (int i = 0; i < p1.length; i++) { float d = p1[i] - p2[i]; sum += d * d; } return sum; } }