Java Utililty Methods Double to Long

List of utility methods to do Double to Long

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Description

The list of methods to do Double to Long are organized into topic(s).

Method

ObjectdoubleToLong(Double aVal)
if the double can safely be converted to a Long then do it. 
if (Double.compare(aVal, Math.ceil(aVal)) == 0) {
    return aVal.longValue();
} else
    return aVal;
LongdoubleToLong(double d)
double To Long 
if (d >= Long.MIN_VALUE && d <= Long.MAX_VALUE) {
    return (long) d;
return null;
long[]doubleToLong(double[] values)
double To Long 
if (values == null) {
    return null;
long[] results = new long[values.length];
for (int i = 0; i < values.length; i++) {
    results[i] = (long) values[i];
return results;
...
longdoubleToLong(final double d)
double To Long 
if (d > Long.MAX_VALUE || d < Long.MIN_VALUE)
    throw new IllegalArgumentException("floating point value is too large to be converted to a Long.");
double x = ((Double) d).longValue();
if (x != d && d < 0.0)
    --x;
return (long) x;
longDoubleToLong_With_Little_Endian(double dd)
Double To Lon Wit Littl Endian 
return Long.reverseBytes(Double.doubleToLongBits(dd));
long[]doubleToLongArray(final double value)
double To Long Array 
final double d = (value == 0.0) ? 0.0 : value; 
final long[] array = { Double.doubleToLongBits(d) }; 
return array;
longdoubleToLongBits(double val)
double To Long Bits 
String dbl = String.valueOf(val);
int decimpoints = dbl.indexOf(".") > -1 ? dbl.split("\\.")[1].length() : 1;
long factor = (long) Math.pow(10, decimpoints);
val = val * factor;
return Math.round(val);
longdoubleToLongBits(double value)
double To Long Bits 
return Double.doubleToLongBits(value);
longdoubleToLongBits(final double d)
Returns the representation of the specified floating-point value according to the IEEE 754 floating-point "double format" bit layout, after first mapping -0.0 to 0.0. 
return ((d == 0.0d) ? 0l : Double.doubleToLongBits(d));
longdoubleToLongBits(final double v)
double To Long Bits 
if (Double.isNaN(v)) {
    return 0x0FFFL << 51;
long sign = (v < 0 ? 0x1L << 63 : 0);
long exponent = 0;
double absV = Math.abs(v);
if (Double.isInfinite(v)) {
    exponent = 0x07FFL << 52;
...