Java Utililty Methods Integer to Binary

List of utility methods to do Integer to Binary

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Description

The list of methods to do Integer to Binary are organized into topic(s).

Method

Stringint2binString(int x)
intbin String 
String s = "";
for (int ii = 0; ii < 32; ii++) {
    if ((ii > 0) && (ii % 4 == 0)) {
        s = " " + s;
    s = hex_digit[(x & (1 << ii)) >>> ii] + s;
return s;
...
StringintegerToBin(int value)
integer To Bin 
return Long.toBinaryString(0x0000000100000000L | ((value) & 0x00000000FFFFFFFFL)).substring(1);
StringintegerToBinaryString(int value)
integer To Binary String 
return (value < 0 ? "1" : "0") + Integer.toBinaryString(Math.abs(value));
StringintegerToBinaryString(int value, int numberOfBits)
Converts a value from a normal integer to a binary value of type String. 
StringBuilder stringBuilder = new StringBuilder();
stringBuilder.append(Integer.toBinaryString(value));
while (stringBuilder.length() != numberOfBits) {
    String old = stringBuilder.toString();
    stringBuilder = new StringBuilder();
    stringBuilder.append("0" + old);
String finalizedBinaryValue = stringBuilder.toString();
...
StringintegerToBinString(final int aValue, final int aFieldWidth)
converts an integer to a bin string with leading zeros 
final long mask = (long) (Math.pow(2.0, aFieldWidth) - 1L);
StringBuilder sb = new StringBuilder(Long.toBinaryString(aValue & mask));
int numberOfLeadingZeros = Math.max(0, aFieldWidth - sb.length());
for (; numberOfLeadingZeros > 0; numberOfLeadingZeros--) {
    sb.insert(0, '0');
return sb.toString();
StringintToBinary(int binary, int digits)
Converts the given integer to a String representing a binary number with the specified number of digits For example when using 4 digits the binary 1 is 0001 
String temp = Integer.toBinaryString(binary);
int foundDigits = temp.length();
String returner = temp;
for (int i = foundDigits; i < digits; i++) {
    returner = "0" + returner;
return returner;
char[]intToBinary(int i)
int To Binary 
char[] values = new char[32];
for (int pos = 31; pos >= 0; pos--, i >>= 1) {
    if ((i & (int) 0x01) == (int) 1)
        values[pos] = '1';
    else
        values[pos] = '0';
return values;
...
StringintToBinary(int i, int byteLength)
int To Binary 
String binString = Integer.toBinaryString(i);
while (binString.length() < byteLength * 8) {
    binString = "0" + binString;
return binString;
StringintToBinary(long value, int bits)
This method converts int values to binary-string. 
char[] returnValue = new char[bits];
boolean wasNegative = false;
if (value < 0) {
    wasNegative = true;
    ++value;
    value = (value * -1);
for (int i = 0; i < bits; ++i) {
...
StringintToBinString(int val, int width)
int To Bin String 
String str = Integer.toBinaryString(val);
if (str.length() >= width) {
    return str;
return mZeroes.substring(0, width - str.length()) + str;