Java Long Number Parse tryParseLong(String longString, int defaultValue)

Description

Try to parse long string, returning -1 if it fails.

License

Open Source License

Parameter

Parameter	Description
longString	a parameter

Return

The string as a long or -1

Declaration

public static long tryParseLong(String longString, int defaultValue) 

Method Source Code

//package com.java2s;
/**/*w  ww .j  a  v  a  2  s .co m*/
 * Copyright (C) 2014 Julian Zhou <jzhou at techcavern.com>
 *
 * This file is part of PircBotZ.
 *
 * PircBotZ is free software: you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation, either version 3 of the License, or
 * (at your option) any later version.
 *
 * PircBotZ is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
 * GNU General Public License for more details.
 *
 * You should have received a copy of the GNU General Public License
 * along with PircBotZ. If not, see <http://www.gnu.org/licenses/>.
 */

public class Main {
    /**
     * Try to parse long string, returning -1 if it fails.
     * @param longString
     * @return The string as a long or -1
     */
    public static long tryParseLong(String longString, int defaultValue) {
        try {
            return Long.parseLong(longString);
        } catch (NumberFormatException e) {
            return defaultValue;
        }
    }
}

Related

1. convertLong(String str, long defaults)
2. convertLong(String valueAsString)
3. longFromString(String which, String s)
4. longFromStringWithoutThrow(String longVal)
5. tryParseLong(Object obj, Long defaultVal)
6. tryParseLong(String longValue)
7. TryParseLong(String str, long[] n)