Java Utililty Methods Map to String

List of utility methods to do Map to String

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Description

The list of methods to do Map to String are organized into topic(s).

Method

MaptoStringMap(Map map)
Transform a map to a string map. 
Map<String, String> stringMap = new HashMap<>();
for (Map.Entry<?, ?> entry : map.entrySet()) {
    stringMap.put(entry.getKey().toString(), entry.getValue().toString());
return stringMap;
MaptoStringMap(Map src)
to String Map 
Map<String, String> dst = new HashMap<String, String>();
Set<?> entrySet = src.entrySet();
for (Object object : entrySet) {
    if (object != null && object instanceof Entry<?, ?>) {
        Entry<?, ?> entry = (Entry<?, ?>) object;
        Object key = entry.getKey();
        Object value = entry.getValue();
        if (key != null) {
...
MaptoStringMap(Properties properties)
to String Map 
Map<String, String> map = new HashMap<String, String>();
for (Object key : properties.keySet()) {
    map.put((String) key, properties.getProperty((String) key));
return map;
MaptoStringMap(String... pairs)
to String Map 
Map<String, String> parameters = new java.util.HashMap<String, String>();
if (pairs.length > 0) {
    if (pairs.length % 2 != 0) {
        throw new IllegalArgumentException("pairs must be even.");
    for (int i = 0; i < pairs.length; i = i + 2) {
        parameters.put(pairs[i], pairs[i + 1]);
return parameters;
MaptoStringMap(String... pairs)
to String Map 
Map<String, String> parameters = new HashMap<String, String>();
if (pairs.length > 0) {
    if (pairs.length % 2 != 0) {
        throw new IllegalArgumentException("pairs must be even.");
    for (int i = 0; i < pairs.length; i = i + 2) {
        parameters.put(pairs[i], pairs[i + 1]);
return parameters;