Java Number Format Pattern formatWith6Digits(String input)

Here you can find the source of formatWith6Digits(String input)

Description

format With Digits

License

Open Source License

Parameter

Parameter Description
input a parameter

Declaration

public static double formatWith6Digits(String input) 

Method Source Code

//package com.java2s;
/**//from   www . java 2s  .  co m
*    Copyright (c) 2011-2014, OpenIoT
*   
*    This file is part of OpenIoT.
*
*    OpenIoT is free software: you can redistribute it and/or modify
*    it under the terms of the GNU Lesser General Public License as published by
*    the Free Software Foundation, version 3 of the License.
*
*    OpenIoT is distributed in the hope that it will be useful,
*    but WITHOUT ANY WARRANTY; without even the implied warranty of
*    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
*    GNU Lesser General Public License for more details.
*
*    You should have received a copy of the GNU Lesser General Public License
*    along with OpenIoT.  If not, see <http://www.gnu.org/licenses/>.
*
*     Contact: OpenIoT mailto: info@openiot.eu
*/

import java.text.DecimalFormat;

public class Main {
    /**
     *
     * @param input
     * @return
     */
    public static double formatWith6Digits(String input) {
        DecimalFormat df = new DecimalFormat("###.000000");
        double input_double = Double.parseDouble(input);
        String result = df.format(input_double);
        double result_double = Double.parseDouble(result);
        return result_double;
    }
}

Related

  1. formatThousands(String inValue)
  2. formatTime(long endTime, long startTime)
  3. formatTokens(long tokens)
  4. formatValue(int value)
  5. formatValue(Object value)
  6. getBigDecimalFromString(String numericValue, String numberFormat)
  7. getDataFormat(final boolean grouped, final boolean isFloat, int declen)
  8. getDefaultDecimalFormat()
  9. getExponentialFormat(int precision)