Java Number Parse isNumeric(String str)

Here you can find the source of isNumeric(String str)

Description

Works out of a string could be parsed a Number

License

Apache License

Parameter

Parameter Description
str a parameter

Declaration

private static boolean isNumeric(String str) 

Method Source Code


//package com.java2s;
/*/*from   www. j  a  v  a  2 s .c om*/
 * This file is licensed under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.text.NumberFormat;

import java.text.ParsePosition;

public class Main {
    /**
     * Works out of a string could be parsed a Number
     * @param str
     * @return
     */
    private static boolean isNumeric(String str) {
        boolean isnumeric = false;
        try {
            NumberFormat formatter = NumberFormat.getInstance();
            ParsePosition pos = new ParsePosition(0);
            formatter.parse(str, pos);
            isnumeric = (str.length() == pos.getIndex() ? true : false);
        } catch (Exception e) {
            isnumeric = false;
        }
        return isnumeric;
    }
}

Related

  1. isNumber(final String str)
  2. isNumber(String str)
  3. isNumeric(Class cls)
  4. isNumeric(final String str)
  5. isNumeric(String str)
  6. isNumeric(String str)
  7. isNumeric(String value, Locale locale)
  8. isParsable(Object parser, String str)
  9. toNumber(char letter)