Java Regex Double Validate parseDouble(String str)

Here you can find the source of parseDouble(String str)

Description

parse Double

License

Open Source License

Declaration

public static double parseDouble(String str) 

Method Source Code

//package com.java2s;
/*/*from w  w w . j a v a2 s. co m*/
    
Copyright (c) 2000-2014 Board of Trustees of Leland Stanford Jr. University,
all rights reserved.
    
Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:
    
The above copyright notice and this permission notice shall be included in
all copies or substantial portions of the Software.
    
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.  IN NO EVENT SHALL
STANFORD UNIVERSITY BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY,
WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR
IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
    
Except as contained in this notice, the name of Stanford University shall not
be used in advertising or otherwise to promote the sale, use or other dealings
in this Software without prior written authorization from Stanford University.
    
*/

import java.util.regex.*;

public class Main {
    private static Pattern BUGGY_DOUBLE_PAT1 = Pattern.compile(
            "2\\.?2\\.?2\\.?5\\.?0\\.?7\\.?3\\.?8\\.?5\\.?8\\.?5\\.?0\\.?7\\.?2\\.?0\\.?1\\.?2\\d*[eE]-0*[23]\\d\\d");
    private static Pattern BUGGY_DOUBLE_PAT2 = Pattern.compile("\\.0{100,}22250738585072012");

    public static double parseDouble(String str) {
        if (isBuggyDoubleString(str)) {
            throw new NumberFormatException("Buggy double string");
        }
        return Double.parseDouble(str);
    }

    public static boolean isBuggyDoubleString(String str) {
        Matcher m1 = BUGGY_DOUBLE_PAT1.matcher(str);
        if (m1.find()) {
            return true;
        }
        Matcher m2 = BUGGY_DOUBLE_PAT2.matcher(str);
        return m2.find();
    }
}

Related

  1. parseDouble(final String text)
  2. parseDouble(Object object)
  3. parseDouble(Object value, Double replace)
  4. parseDouble(String myString)
  5. parseDouble(String s)
  6. parseDoubleList(String list)