Java Regex Number Validate isNumeric(String input)

Description

is Numeric

License

Apache License

Declaration

private static boolean isNumeric(String input) 

Method Source Code

//package com.java2s;
/*! ******************************************************************************
 *
 * Pentaho Data Integration//w  w  w.ja va2s .  c  om
 *
 * Copyright (C) 2002-2015 by Pentaho : http://www.pentaho.com
 *
 *******************************************************************************
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with
 * the License. You may obtain a copy of the License at
 *
 *    http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 ******************************************************************************/

import java.util.regex.Pattern;

public class Main {
    private static final Pattern NUMERIC_PATTERN = Pattern.compile("\\d+");

    private static boolean isNumeric(String input) {
        boolean result = false;
        if (input != null) {
            result = NUMERIC_PATTERN.matcher(input).matches();
        }
        return result;
    }
}

Related

1. isNumber_Lowerletter_Underline(String str)
2. isNumberForLength(String numStr, int length)
3. isNumberLiteral(String s)
4. isNumberOfShownValue(String inputString)
5. isNumeric(String as_argument)
6. isNumeric(String number)
7. isNumeric(String s)
8. isNumeric(String str)
9. isNumeric(String str)