Java Regex String Replace Whitespace replaceWhiteSpaces(String str)

Description

replace White Spaces

License

Apache License

Parameter

Parameter	Description
str	a string where replace whitespaces are to be replaced.

Return

a string with whitespaces replaced by regular spaces.

Declaration

public static String replaceWhiteSpaces(String str) 

Method Source Code

//package com.java2s;
/*/*from  w  w  w. ja  v a  2  s. c o  m*/
 *  Copyright 2014 Carnegie Mellon University
 *
 *  Licensed under the Apache License, Version 2.0 (the "License");
 *  you may not use this file except in compliance with the License.
 *  You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 *  Unless required by applicable law or agreed to in writing, software
 *  distributed under the License is distributed on an "AS IS" BASIS,
 *  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *  See the License for the specific language governing permissions and
 *  limitations under the License.
 */

import java.util.regex.Pattern;

public class Main {
    public static final Pattern PATTERN_WHITESPACE = Pattern.compile("[\\s\n\r\t]");

    /**
     * @param  str  a string where replace whitespaces are to be replaced.
     * @return a string with whitespaces replaced by regular spaces.
     */
    public static String replaceWhiteSpaces(String str) {
        return PATTERN_WHITESPACE.matcher(str).replaceAll(" ");
    }
}

Related

1. replaceWhitespace(final String value, final boolean stripExtras)
2. replaceWhitespace(String searchTerm)
3. replaceWhiteSpaces(final String value, final String replaceBy)
4. replaceWhitespaces(String inString, String with)
5. replaceWhitespaces(String inString, String with)
6. replaceWhiteSpacesByMinusSign(final String value)