Java Regex Time Validate parseTime(String s)

Description

parse Time

License

Open Source License

Declaration

public static long parseTime(String s) 

Method Source Code

//package com.java2s;
/*  This file is part of Catacombs.
    // www  .ja v a 2  s  .co m
Catacombs is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
    
Catacombs is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU General Public License for more details.
    
You should have received a copy of the GNU General Public License
along with Catacombs.  If not, see <http://www.gnu.org/licenses/>.
 * 
 * @author John Keay  <>(@Steeleyes, @Blockhead2)
 * @copyright Copyright (C) 2011
 * @license GNU GPL <http://www.gnu.org/licenses/>
 */

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static long parseTime(String s) {
        Pattern p = Pattern.compile("(\\d+)([smhd])");
        Matcher m = p.matcher(s);
        long num = 0;
        while (m.find()) {
            int i = Integer.parseInt(m.group(1));
            String unit = m.group(2);
            //    System.out.println("[Catacombs]   parse "+unit+" "+i);

            if (unit.equals("m"))
                i = i * 60;
            if (unit.equals("h"))
                i = i * 60 * 60;
            if (unit.equals("d"))
                i = i * 60 * 60 * 24;
            num += i;
        }
        //System.out.println("[Catacombs] Parse "+s+" = "+num+"sec(s)");
        return num * 1000;
    }
}

Related

1. parseTime(String str)
2. parseTime(String t)
3. parseTime(String value)
4. parseTimeDifference(String input)