Java Resource Load getResourceByZip(final ZipInputStream zipIN, final String resourcePath)

Description

get Resource By Zip

License

Apache License

Declaration

public static InputStream getResourceByZip(final ZipInputStream zipIN, final String resourcePath)
        throws IOException 

Method Source Code

//package com.java2s;
/*/*from w w  w  . j a v a2s.  c om*/
 * Copyright 2008-2009 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.io.*;

import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class Main {

    public static InputStream getResourceByZip(final ZipInputStream zipIN, final String resourcePath)
            throws IOException {
        ZipEntry e = null;
        while ((e = zipIN.getNextEntry()) != null) {
            if (e.getName().equals(resourcePath) == true) {
                return zipIN;
            }
            zipIN.closeEntry();
        }
        return null;
    }
}

Related

1. getResourceAsTempFile(Object context, String resourceName)
2. getResourceBundle(String baseName)
3. getResourceBundle(String resourceURI, Locale targetLocale)
4. getResourceBundleForLoc(String language, String fileName)
5. getResourceBytes(String path)
6. getResourceDirectory()
7. getResourceFile(Class clazz, String path)
8. getResourceFile(Class theClass, String fileName)
9. getResourceFile(String relativeResourceFilePathname)