Java Resource Path Get deserialize(Class parentOfResource, String resourcePath, Class targetClass)

Description

deserialize

License

Open Source License

Declaration

public static <T> T deserialize(Class<?> parentOfResource, String resourcePath, Class<T> targetClass) 

Method Source Code

//package com.java2s;
//License from project: Open Source License 

import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
import java.net.URL;
import static java.lang.String.format;
import static java.util.Objects.requireNonNull;

public class Main {
    public static final ObjectMapper objectMapper = new ObjectMapper();

    public static <T> T deserialize(Class<?> parentOfResource, String resourcePath, Class<T> targetClass) {
        URL resourceUrl = parentOfResource.getResource(resourcePath);
        requireNonNull(resourceUrl,/* ww w.  j  av  a  2 s. c  om*/
                format("resource '%s' of class '%s' not found", resourcePath, parentOfResource.getCanonicalName()));
        try {
            return objectMapper.readValue(resourceUrl, targetClass);
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }
}

Related

1. classToResource(String className)
2. existsResource(String pathName)
3. getAbsolutePathFromResource(Class reference, String resource)
4. getAbsoluteResource(String path)
5. getAlternateResourceFile(final String resourcePath)