Java String Chop at Word chopAtWord(String string, int length, int minLength)

Description

chop At Word

License

Open Source License

Declaration

public static String chopAtWord(String string, int length, int minLength) 

Method Source Code

//package com.java2s;
/**//from  w  ww.  j a  v a 2 s. c om
 * $Revision $
 * $Date $
 *
 * Copyright (C) 2005-2010 Jive Software. All rights reserved.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    public static String chopAtWord(String string, int length, int minLength) {
        if (length < 2)
            throw new IllegalArgumentException((new StringBuilder()).append("Length specified (").append(length)
                    .append(") must be > 2").toString());
        if (minLength >= length)
            throw new IllegalArgumentException("minLength must be smaller than length");
        int sLength = string != null ? string.length() : -1;
        if (sLength < 1)
            return string;
        if (minLength != -1 && sLength < minLength)
            return string;
        if (minLength == -1 && sLength < length)
            return string;

        char charArray[] = string.toCharArray();
        if (sLength > length) {
            sLength = length;
            for (int i = 0; i < sLength - 1; i++) {
                if (charArray[i] == '\r' && charArray[i + 1] == '\n')
                    return string.substring(0, i + 1);
                if (charArray[i] == '\n')
                    return string.substring(0, i);
            }

            if (charArray[sLength - 1] == '\n')
                return string.substring(0, sLength - 1);
            for (int i = sLength - 1; i > 0; i--)
                if (charArray[i] == ' ')
                    return string.substring(0, i).trim();

        } else if (minLength != -1 && sLength > minLength) {
            for (int i = 0; i < minLength; i++)
                if (charArray[i] == ' ')
                    return string;

        }
        if (minLength > -1 && minLength <= string.length())
            return string.substring(0, minLength);
        else
            return string.substring(0, length);
    }

    public static String chopAtWord(String string, int length) {
        return chopAtWord(string, length, -1);
    }
}

Related

1. chopAtWord(String string, int length)
2. chopAtWord(String string, int length)
3. chopAtWord(String string, int length, int minLength)
4. chopAtWordsAround(String input, String wordList[], int numChars)
5. chopAtWordsAround(String input, String[] wordList, int numChars)