Here you can find the source of indexOfWord(String word, String string)
public static int indexOfWord(String word, String string)
//package com.java2s; /*/* w w w .j a v a 2 s . c o m*/ * Copyright: (c) 2002-2006 Mayo Foundation for Medical Education and * Research (MFMER). All rights reserved. MAYO, MAYO CLINIC, and the * triple-shield Mayo logo are trademarks and service marks of MFMER. * * Except as contained in the copyright notice above, the trade names, * trademarks, service marks, or product names of the copyright holder shall * not be used in advertising, promotion or otherwise in connection with * this Software without prior written authorization of the copyright holder. * * Licensed under the Eclipse Public License, Version 1.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.eclipse.org/legal/epl-v10.html * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.util.*; public class Main { /** returns the index (word count) of word in the string. If word is not in the string then it returns -1. If word exists inside string that does not mean that it is considered a 'word' in the string. Uses StringTokenizer */ public static int indexOfWord(String word, String string) { word = word.toLowerCase().trim(); String wordInString; StringTokenizer st = new StringTokenizer(string); for (int i = 0; st.hasMoreElements(); i++) { wordInString = st.nextToken().toLowerCase().trim(); if (word.equals(wordInString)) return i; } return -1; } }