Java String Levenshtein Distance levenshteinDistance(String s, String t)

Here you can find the source of levenshteinDistance(String s, String t)

Description

levenshtein Distance

License

Open Source License

Declaration

public static int levenshteinDistance(String s, String t) 

Method Source Code

//package com.java2s;
/*//from   w w w .  jav a 2  s .  c  o m
 * Copyright (c) Erasmus MC
 *
 * This file is part of TheMatrix.
 *
 * TheMatrix is free software: you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation, either version 3 of the License, or
 * (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
 * GNU General Public License for more details.
 *
 * You should have received a copy of the GNU General Public License
 * along with this program. If not, see <http://www.gnu.org/licenses/>.
 */

public class Main {
    public static int levenshteinDistance(String s, String t) {

        int d[][]; // matrix

        int n; // length of s

        int m; // length of t

        int i; // iterates through s

        int j; // iterates through t

        char s_i; // ith character of s

        char t_j; // jth character of t

        int cost; // cost

        n = s.length();

        m = t.length();

        if (n == 0) {

            return m;

        }

        if (m == 0) {

            return n;

        }

        d = new int[n + 1][m + 1];

        for (i = 0; i <= n; i++) {

            d[i][0] = i;

        }

        for (j = 0; j <= m; j++) {

            d[0][j] = j;

        }

        for (i = 1; i <= n; i++) {

            s_i = s.charAt(i - 1);

            for (j = 1; j <= m; j++) {

                t_j = t.charAt(j - 1);

                if (s_i == t_j) {

                    cost = 0;

                }

                else {

                    cost = 1;

                }

                d[i][j] = Math.min(d[i - 1][j] + 1, Math.min(d[i][j - 1] + 1, d[i - 1][j - 1] + cost));

            }

        }

        return d[n][m];

    }
}

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