Java String Split by Separator split(String s, char separator)

Here you can find the source of split(String s, char separator)

Description

split

License

Open Source License

Declaration

public static String[] split(String s, char separator) 

Method Source Code

//package com.java2s;
/*//from  w  ww . ja  va 2 s  .  com
 * Copyright (c) 2007 Yaroslav Stavnichiy, yarosla@gmail.com
 *
 * Latest version of this software can be obtained from:
 *   http://web-tec.info/WikiParser/
 *
 * Permission is hereby granted, free of charge, to any person obtaining a copy
 * of this software and associated documentation files (the "Software"), to deal
 * in the Software without restriction, including without limitation the rights
 * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
 * copies of the Software, and to permit persons to whom the Software is
 * furnished to do so, subject to the following conditions:
 *
 * The above copyright notice and this permission notice shall be included in all
 * copies or substantial portions of the Software.

 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
 * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
 * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
 * SOFTWARE.
 *
 * If you make use of this code, I'd appreciate hearing about it.
 * Comments, suggestions, and bug reports welcome: yarosla@gmail.com
 */

import java.util.*;

public class Main {
    public static String[] split(String s, char separator) {
        // this is meant to be faster than String.split() when separator is not regexp
        if (s == null)
            return null;
        ArrayList<String> parts = new ArrayList<String>();
        int beginIndex = 0, endIndex;
        while ((endIndex = s.indexOf(separator, beginIndex)) >= 0) {
            parts.add(s.substring(beginIndex, endIndex));
            beginIndex = endIndex + 1;
        }
        parts.add(s.substring(beginIndex));
        String[] a = new String[parts.size()];
        return parts.toArray(a);
    }
}

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