Java URI from toURI(String location)

Description

Create a URI instance for the given location String, replacing spaces with "%20" URI encoding first.

License

Apache License

Parameter

Parameter	Description
location	the location String to convert into a URI instance

Exception

Parameter	Description
URISyntaxException	if the location wasn't a valid URI

Return

the URI instance

Declaration

public static URI toURI(String location) throws URISyntaxException 

Method Source Code

//package com.java2s;
/**//from  w w w .j a  va 2  s  . co m
 * Copyright 2008-2015 Jordi Hern?ndez Sell?s, Ibrahim Chaehoi
 * 
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file
 * except in compliance with the License. You may obtain a copy of the License at
 * 
 *    http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software distributed under the
 * License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND,
 * either express or implied. See the License for the specific language governing permissions
 * and limitations under the License.
 */

import java.net.URI;
import java.net.URISyntaxException;
import java.net.URL;

public class Main {
    /**
     * Create a URI instance for the given URL, replacing spaces with "%20" URI
     * encoding first.
     * <p>
     * Furthermore, this method works on JDK 1.4 as well, in contrast to the
     * {@code URL.toURI()} method.
     * 
     * @param url
     *            the URL to convert into a URI instance
     * @return the URI instance
     * @throws URISyntaxException
     *             if the URL wasn't a valid URI
     * @see java.net.URL#toURI()
     */
    public static URI toURI(URL url) throws URISyntaxException {
        return toURI(url.toString());
    }

    /**
     * Create a URI instance for the given location String, replacing spaces
     * with "%20" URI encoding first.
     * 
     * @param location
     *            the location String to convert into a URI instance
     * @return the URI instance
     * @throws URISyntaxException
     *             if the location wasn't a valid URI
     */
    public static URI toURI(String location) throws URISyntaxException {
        return new URI(location.replace(" ", "%20"));
    }
}

Related

1. toUri(String endpoint, Protocol protocol)
2. toUri(String ip, String path)
3. toURI(String location)
4. toURI(String location)
5. toURI(String location)
6. toURI(String location)
7. toURI(String path)
8. toUri(String path)
9. toURI(String s)