Java URL Unescape unEscapeURL(String input)

Here you can find the source of unEscapeURL(String input)

Description

un Escape URL

License

Apache License

Declaration

public static String unEscapeURL(String input) 

Method Source Code

//package com.java2s;
/*/*from www .  ja va 2  s .  co m*/
 * Copyright 2000-2015 JetBrains s.r.o.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    public static String unEscapeURL(String input) {
        return input.replaceAll("%20", " ");
    }
}

Related

  1. unescapeURL(String s)