Java XML Child Element Text getChildText(Element parent, String name)

Description

get Child Text

License

Apache License

Declaration

public static String getChildText(Element parent, String name)

Method Source Code

//package com.java2s;
/*//  w w  w  . j a  va2s . co  m
 * Copyright 2013 Keith D Swenson
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *    http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 * Contributors Include: Shamim Quader, Sameer Pradhan, Kumar Raja, Jim Farris,
 * Sandia Yang, CY Chen, Rajiv Onat, Neal Wang, Dennis Tam, Shikha Srivastava,
 * Anamika Chaudhari, Ajay Kakkar, Rajeev Rastogi
 */

import org.w3c.dom.Element;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static String getChildText(Element parent, String name) {
        Element child = getChildElement(parent, name);
        if (child == null) {
            return "";
        }
        return textValueOf(child, true);
    }

    public static Element getChildElement(Element parent, String name) {
        NodeList childNdList = parent.getChildNodes();
        if (childNdList == null) {
            return null;
        }
        for (int i = 0; i < childNdList.getLength(); i++) {
            org.w3c.dom.Node n = childNdList.item(i);

            if (n == null) {
                //apparently, there is some situations where the Nodellist will return
                //a null.  Have gotten a null opinter exception on the line below.
                //don't understand how it happens, but this seems to happen, just skip it.
                continue;
            }

            if (n.getNodeType() != org.w3c.dom.Node.ELEMENT_NODE) {
                continue;
            }
            if (name.equals(n.getLocalName())) {
                return (Element) n;
            }
            if (name.equals(n.getNodeName())) {
                return (Element) n;
            }
        }
        return null;
    }

    /**
    * Returns the text of all the chidren of a node as a single string
    *
    * @param node is the parent of the text
    * @param nodeName
    */
    public static String textValueOf(Node node, boolean trim) {
        // unfold the loop.  99.9% of the time, the XML will have a
        // single text node.  Memory is much more efficiently handled
        // if the string from that text node is used directly, instead
        // of being copied into the string buffer.   Unfold the loop,
        // and if there is a single child node, simply return that
        // value.
        Node child = skipToNextTextNode(node.getFirstChild());
        if (child == null) {
            return "";
        }
        Node nextChild = skipToNextTextNode(child.getNextSibling());
        if (nextChild == null) {
            if (trim) {
                return child.getNodeValue().trim();
            } else {
                return child.getNodeValue();
            }
        }

        // we have more than one, so make a string buffer to
        // concatenate them together.
        StringBuilder text = new StringBuilder();
        if (trim) {
            text.append(child.getNodeValue().trim());
        } else {
            text.append(child.getNodeValue());
        }
        child = nextChild;
        while (child != null) {
            if (trim) {
                text.append(child.getNodeValue().trim());
            } else {
                text.append(child.getNodeValue());
            }
            child = skipToNextTextNode(child.getNextSibling());
        }
        return text.toString();
    }

    private static Node skipToNextTextNode(Node child) {
        if (child == null) {
            return null;
        }
        while (child.getNodeType() != Node.CDATA_SECTION_NODE && child.getNodeType() != Node.TEXT_NODE) {
            child = child.getNextSibling();
            if (child == null) {
                return null;
            }
        }
        return child;
    }
}

Java XML Child Element Text getChildText(Element parent, String name)

Description

License

Declaration

Method Source Code

Related