Java Utililty Methods XML Has Child

List of utility methods to do XML Has Child

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Description

The list of methods to do XML Has Child are organized into topic(s).

Method

HashtablegetChildHash(Element elem, String elementName, String attrName)
get Child Hash 
if (elem == null)
    return null;
NodeList nl = elem.getChildNodes();
if (nl == null)
    return null;
Hashtable<String, Element> retlist = new Hashtable<String, Element>(100);
for (int n = 0; n < nl.getLength(); n++) {
    Node child = nl.item(n);
...
ElementgetLastVisibleChildElement(Node parent, Hashtable hiddenNodes)
Finds and returns the last visible child element node. 
Node child = parent.getLastChild();
while (child != null) {
    if (child.getNodeType() == Node.ELEMENT_NODE && !isHidden(child, hiddenNodes)) {
        return (Element) child;
    child = child.getPreviousSibling();
return null;
...
booleanhasActivityChildNode(Node node)
Checks whether the node has a child node that represents a BPEL activity. 
boolean foundNonTextChild = false;
for (Node child = node.getFirstChild(); child != null; child = child.getNextSibling()) {
    if (!(child instanceof Text)) {
        if (BPEL_ACTIVITIES.contains(child.getNodeName())) {
            foundNonTextChild = true;
return foundNonTextChild;
booleanhasAnyChildElement(final Element e)
has Any Child Element 
for (Node child = e.getFirstChild(); child != null; child = child.getNextSibling()) {
    if (child instanceof Element) {
        return true;
return false;
booleanhasChild(Element element, String child)
Determine whether a single child is available of a particular type. 
NodeList nodes = element.getChildNodes();
Element ret = null;
for (int i = 0; i < nodes.getLength(); i++) {
    Node childNode = nodes.item(i);
    if (childNode.getNodeName().equals(child) && childNode.getNodeType() == Node.ELEMENT_NODE) {
        if (ret != null) {
            throw new Exception("Child element '" + child + "' present multiple times");
        } else {
...
booleanhasChild(Element node, String name)
This method checks whether the given element node has a child element with the given name. 
List<Element> children = getDirectChildElementsByTag(node, DOM_WILDCARD);
for (Element e : children) {
    if (e.getNodeName().equals(name)) {
        return true;
return false;
booleanhasChild(Element parent, String nodeName)
has Child 
NodeList childNodes = parent.getChildNodes();
int length = childNodes.getLength();
for (int i = 0; i < length; i++)
    if (childNodes.item(i).getNodeName().equals(nodeName))
        return true;
return false;
booleanhasChild(Element root, String childName)
has Child 
return (root.getElementsByTagName(childName).getLength() > 0);
booleanhasChild(Element start, String name)
__UNDOCUMENTED__ 
NodeList nl = start.getChildNodes();
int len = nl.getLength();
Node n = null;
for (int i = 0; i < len; i++) {
    n = nl.item(i);
    if (n.getNodeName().equals(name)) {
        return true;
return false;
booleanhasChild(Node n)
has Child 
NodeList nl = n.getChildNodes();
for (int i = 0; i < nl.getLength(); i++) {
    n = nl.item(i);
    if (n.getNodeType() == 1)
        return true;
return false;