Java XML Node Find findNodeLong(Node node)

Here you can find the source of findNodeLong(Node node)

Description

find Node Long

License

Open Source License

Declaration

public static long findNodeLong(Node node) 

Method Source Code

//package com.java2s;
/*/*  www.j a va 2  s .  c  om*/
 Copyright (c) 2011 Bit Bunker
    
Permission is hereby granted, free of charge, to any person obtaining a copy of
this software and associated documentation files (the "Software"), to deal in
the Software without restriction, including without limitation the rights to
use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies
of the Software, and to permit persons to whom the Software is furnished to do
so, subject to the following conditions:
    
The above copyright notice and this permission notice shall be included in all
copies or substantial portions of the Software.
    
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
SOFTWARE.
 */

import org.w3c.dom.Node;

public class Main {
    public static long findNodeLong(Node node) {
        long value = 0;
        String text = findNodeText(node);

        if (text != null && !text.equals(""))
            value = Long.parseLong(text);

        return value;
    }

    public static String findNodeText(Node node) {
        String text = null;
        Node textNode = findChild(node, "#text");

        if (textNode != null)
            text = textNode.getNodeValue();

        return text;
    }

    public static Node findChild(Node parent, String childName) {
        Node childNode = null;

        if (parent != null) {
            for (int i = 0; i < parent.getChildNodes().getLength(); i++) {
                Node candidateNode = parent.getChildNodes().item(i);

                if (candidateNode.getNodeName().equals(childName)) {
                    childNode = candidateNode;
                    break;
                }
            }
        }

        return childNode;
    }
}

Related

  1. findNodeByName(Document doc, String pathExpression)
  2. findNodeByTagName(Document document, String tagName)
  3. findNodeByXpath(org.w3c.dom.Document doc, String xpathEx)
  4. findNodeIndex(Node node)
  5. findNodeIndex(Node node)
  6. findNodesByTagName(Document document, String tagName)
  7. findNodesNamed(Node node, String lookForName, Collection ret)
  8. findNodeValue(Node aNode, String aName)
  9. findNodeWithAttrValue(Document doc, String elementName, String attrName, String attrValue)