Java XML Parse Stream parseXml(InputStream src)

Description

parse Xml

License

Open Source License

Declaration

public static Node parseXml(InputStream src) 

Method Source Code

//package com.java2s;
/*/*  w w  w  .j  a v a  2 s . c o  m*/
 * #%L
 * Xacml4J Core Engine Implementation
 * %%
 * Copyright (C) 2009 - 2014 Xacml4J.org
 * %%
 * This program is free software: you can redistribute it and/or modify
 * it under the terms of the GNU Lesser General Public License as
 * published by the Free Software Foundation, either version 3 of the
 * License, or (at your option) any later version.
 * 
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Lesser Public License for more details.
 * 
 * You should have received a copy of the GNU General Lesser Public
 * License along with this program.  If not, see
 * <http://www.gnu.org/licenses/lgpl-3.0.html>.
 * #L%
 */

import java.io.InputStream;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Node;
import org.xml.sax.InputSource;
import com.google.common.base.Preconditions;

public class Main {
    private static DocumentBuilderFactory documentBuilderFactory;

    public static Node parseXml(InputStream src) {
        if (src == null) {
            return null;
        }
        return parseXml(new InputSource(src));
    }

    public static Node parseXml(InputSource src) {
        Preconditions.checkNotNull(src);
        DocumentBuilder documentBuilder = null;
        try {
            documentBuilder = documentBuilderFactory.newDocumentBuilder();
        } catch (ParserConfigurationException e) {
            throw new IllegalStateException(String.format(
                    "Failed to build %s", DocumentBuilder.class.getName()),
                    e);
        }
        try {
            return documentBuilder.parse(src);
        } catch (Exception e) {
            throw new IllegalArgumentException(String.format(
                    "Failed to parse DOM from string: \"%s\"", src), e);
        }
    }
}

Related

1. parseXml(InputStream in)
2. parseXML(InputStream in)
3. parseXml(InputStream inputStream, boolean validating)
4. parseXML(InputStream is)
5. parseXML(InputStream is, String[] tagNames)
6. parseXMLFromStream(InputStream stream)
7. parseXmlInputStream(InputStream inputStream)
8. parseXmlInputStream(InputStream inputStream)
9. parseXMLResource(final InputStream inputStream)