Find the first occurrence of sub in b Work in progress - Java java.lang

Java examples for java.lang:byte Array

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Description

Find the first occurrence of sub in b Work in progress

Demo Code

/*/*from   ww w . j  a  va 2 s  .  com*/
 This file is part of p300.


 p300 is free software: you can redistribute it and/or modify
 it under the terms of the GNU General Public License as published by
 the Free Software Foundation, either version 3 of the License, or
 (at your option) any later version.

 p300 is distributed in the hope that it will be useful,
 but WITHOUT ANY WARRANTY; without even the implied warranty of
 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 GNU General Public License for more details.

 You should have received a copy of the GNU General Public License
 along with p300.  If not, see <http://www.gnu.org/licenses/>.
 */
//package com.java2s;

public class Main {
    public static void main(String[] argv) throws Exception {
        byte[] b = new byte[] { 34, 35, 36, 37, 37, 37, 67, 68, 69 };
        byte[] sub = new byte[] { 34, 35, 36, 37, 37, 37, 67, 68, 69 };
        System.out.println(indexOf(b, sub));
    }

    /**
     * Find the first occurrence of sub in b
     * Work in progress
     * @param b
     * @param sub
     * @return Position of the first match or -1 if not found
     */
    public static int indexOf(byte[] b, byte[] sub) {
        if (b == null || sub == null) {
            return -1;
        }

        for (int i = 0; i < b.length - sub.length + 1; i++) {
            boolean matches = true;
            for (int j = 0; j < sub.length; j++) {
                if (b[i + j] != sub[j]) {
                    matches = false;
                }
            }
            if (matches) {
                return i;
            }
        }

        return -1;
    }
}

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