Data not found exception : Exception « PL SQL Programming « Oracle PL/SQL Tutorial






SQL>
SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL primary key,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ('01','Jason',    'Martin',  to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto',  'Programmer')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('02','Alison',   'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('03','James',    'Smith',   to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('04','Celia',    'Rice',    to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('05','Robert',   'Black',   to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('06','Linda',    'Green',   to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York',  'Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('07','David',    'Larry',   to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York',  'Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('08','James',    'Cat',     to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')
  3  /

1 row created.

SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /


ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester

8 rows selected.

SQL>
SQL>
SQL> SET SERVEROUTPUT ON ESCAPE OFF
SQL>
SQL> DECLARE
  2     v_employee EMPLOYEE.FIRST_NAME%TYPE;
  3  BEGIN
  4
  5     -- the first nested block
  6     BEGIN
  7        SELECT first_name
  8        INTO v_employee
  9        FROM EMPLOYEE
 10        WHERE UPPER(last_name) = 'CAT';
 11     EXCEPTION
 12        WHEN NO_DATA_FOUND
 13        THEN
 14           DBMS_OUTPUT.PUT_LINE('EXCEPTION HANDLER for nested block 1');
 15           DBMS_OUTPUT.PUT_LINE('     ');
 16           NULL;
 17     END;
 18
 19     -- the second nested block
 20     BEGIN
 21        SELECT first_name
 22        INTO v_employee
 23        FROM EMPLOYEE
 24        WHERE UPPER(last_name) = 'HARDMAN';
 25
 26     EXCEPTION
 27        WHEN TOO_MANY_ROWS
 28        THEN
 29           DBMS_OUTPUT.PUT_LINE('     ');
 30           DBMS_OUTPUT.PUT_LINE('EXCEPTION HANDLER for nested block 2');
 31           DBMS_OUTPUT.PUT_LINE('If this is printing, then the both nested');
 32           DBMS_OUTPUT.PUT_LINE('blocks'' exception handler worked!');
 33     END;
 34  END;
 35  /
DECLARE
*
ERROR at line 1:
ORA-01403: no data found
ORA-06512: at line 21


SQL>
SQL>
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
  2  /

Table dropped.








24.14.Exception
24.14.1.Exceptions
24.14.2.Types of more commonly used Exceptions
24.14.3.Exception Handling
24.14.4.The NULL Statement
24.14.5.ZERO_DIVIDE Exception
24.14.6.When the exception occurs, program control passes to the EXCEPTION block where the WHEN clause is examined for a matching exception.
24.14.7.Understanding Different Exception Types
24.14.8.DUP_VAL_ON_INDEX Exception
24.14.9.INVALID_NUMBER Exception
24.14.10.Catch 'divide by zero' exception
24.14.11.OTHERS Exception
24.14.12.Because OTHERS handles all exceptions, you must list it after any specific exceptions in your EXCEPTION block.
24.14.13.Declare variables in exception handler
24.14.14.Data not found exception
24.14.15.Too many rows exception