Java Utililty Methods Array Min Value

int minIndex = 0;
int minValue = arr[0];
for (int i = 1; i < arr.length; i++) {
    if (minValue > arr[i]) {
        minIndex = i;
        minValue = arr[i];
return minIndex;

int r = Integer.MAX_VALUE;
for (int i = 0; i < count; i++)
    r = Math.min(r, arr[i]);
return r;

int minimum = Integer.MAX_VALUE;
for (int i = 0; i < array.length; i++) {
    if (minimum > array[i]) {
        minimum = array[i];
return minimum;

int min = Integer.MAX_VALUE;
for (int i = 0; i < array.length; i++) {
    if (array[i] < min) {
        min = array[i];
return min;

int minValue = array[0];
for (int aVector : array) {
    if (minValue > aVector) {
        minValue = aVector;
return minValue;

int min = Integer.MAX_VALUE;
for (int a : array) {
    if (a < min) {
        min = a;
return min;

if (array == null) {
    throw new IllegalArgumentException("The Array must not be null");
} else if (array.length == 0) {
    throw new IllegalArgumentException("Array cannot be empty.");
int iMin = array[0];
for (int j = 1; j < array.length; j++) {
    if (array[j] < iMin) {
...

int result = Integer.MAX_VALUE;
if (elements != null)
    for (int i : elements)
        result = (result <= i ? result : i);
return result;

int minval = 999999;
if (in != null && x1 >= 0) {
    for (int i = x1; i < Math.min(in.length, x2); i++) {
        if (in[i] != 0)
            minval = Math.min(in[i], minval);
return minval;
...

if (list.length == 0) {
    throw new ArrayIndexOutOfBoundsException(ERROR_MIN_MAX);
int min = list[0];
for (int i = 1; i < list.length; i++) {
    if (list[i] < min)
        min = list[i];
return min;