Java Utililty Methods Array Min Value

if (vals.length == 0) {
    return Double.NaN;
double[] range = range(vals);
return range[0];

int minIdx = -1;
for (int i = 0; i < values.length; i++) {
    if ((minIdx == -1) || (values[i] < values[minIdx])) {
        minIdx = i;
return minIdx;

Arrays.sort(values);
return minOfSortedValues(values);

double min = values[0];
for (double v : values) {
    if (v < min)
        min = v;
return min;

return min(x, true);

double min = doubles[0];
for (final double real : doubles) {
    min = real < min ? real : min;
return min;

Double max = null;
for (Double value : values) {
    if (value == null) {
        continue;
    if (max == null || value < max) {
        max = value;
return max;

if (input == null || input.length < 1) {
    return 0;
double output = input[0];
for (int i = 1; i < input.length; i++) {
    if (input[i] < output) {
        output = input[i];
return output;

double min = nums[0];
for (int i = 1; i < nums.length; ++i) {
    if (nums[i] < min)
        min = nums[i];
return min;

if (tab == null) {
    throw new NullPointerException("Array cannot be null");
if (tab.length == 0) {
    throw new IllegalArgumentException("Array has zero length");
int index = 0;
double max = tab[index];
...