Java Utililty Methods Convert via ByteBuffer

List of utility methods to do Convert via ByteBuffer

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Description

The list of methods to do Convert via ByteBuffer are organized into topic(s).

Method

ByteBuffertoBuffer(boolean[] src, int offset)
to Buffer 
int n = src.length - offset;
ensureSize(n);
buffer.position(0);
for (boolean value : src)
    buffer.put(value ? (byte) 1 : 0);
return buffer;
ByteBuffertoBuffer(byte[] arr)
to Buffer 
ByteBuffer buffer = ByteBuffer.allocate(arr.length);
buffer.put(arr);
buffer.flip();
return buffer.duplicate();
ByteBuffertoBuffer(byte[] arr)
to Buffer 
ByteBuffer buff = createByteBuffer(arr.length);
buff.put(arr);
buff.compact();
return buff;
ByteBuffertoBuffer(int[] array)
to Buffer 
ByteBuffer result = ByteBuffer.allocate(array.length);
for (int i = 0; i < array.length; ++i) {
    result.put((byte) (array[i] & 0xff));
result.flip();
return result;
ByteBuffertoBuffer(Serializable obj)
Convert a serializable object to buffer. 
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(baos);
oos.writeObject(obj);
oos.flush();
ByteBuffer buffer = ByteBuffer.wrap(baos.toByteArray());
oos.close();
baos.close();
return buffer;
...
ByteBuffertoBuffer(String spacedHex)
Convert the spaced hex form of a String into a ByteBuffer. 
return ByteBuffer.wrap(toByteArray(spacedHex));
byte[]toByte(char data)
to Byte 
return ByteBuffer.allocate(2).putChar(0, data).array();
byte[]toByte(final char[] charArray)
Converts a character array to a byte array 
final byte[] byteArray = new byte[charArray.length << 1];
int bpos = 0;
for (final char element : charArray) {
    if ((byte) ((element & 0xFF00) >> 8) != 0) {
        byteArray[bpos] = (byte) ((element & 0xFF00) >> 8);
        bpos++;
    byteArray[bpos] = (byte) (element & 0x00FF);
...
byte[]toByte(int input, int count)
HelperMethod to Convert int to byte[] 
return ByteBuffer.allocate(count).putInt(input).array();
byte[]toByteArray(BitSet bits)
Convert BitSet to byte array 
byte[] result = new byte[(bits.length() + 7) / 8];
for (int i = 0; i < bits.length(); ++i) {
    if (bits.get(i)) {
        result[i / 8] |= 1 << (i % 8);
return result;