Java Double Number Truncate truncate(double value, int precision)

Here you can find the source of truncate(double value, int precision)

Description

truncate

License

Apache License

Declaration

public static double truncate(double value, int precision) 

Method Source Code

//package com.java2s;
/*//  w ww .  j  ava  2  s  .  co m
 * Copyright @ 2006-2010 by The Jxva Framework Foundation
 * 
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * 
 *      http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {

    public static float truncate(float value, int precision) {
        return Float.parseFloat(Double.toString(truncate((double) value, precision)));
    }

    public static double truncate(double value, int precision) {
        String str = Double.toString(value);
        String precisionstr = str.substring(str.indexOf('.') + 1);
        if (precisionstr.length() <= precision) {
            return value;
        } else {
            long tmp = Math.round(value * Math.pow(10, precisionstr.length()));
            for (int i = 0; i < precisionstr.length() - precision - 1; i++) {
                tmp /= 10;
            }
            if (tmp % 10 >= 5) {
                tmp /= 10;
                tmp += 1;
            } else {
                tmp /= 10;
            }
            return ((double) tmp) / Math.pow(10, precision);
        }
    }
}

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  8. truncate(double x)
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