Java Regex Number Validate isNumber(String data)

Description

Using Regex, find if we have a number in the String

License

Open Source License

Parameter

Parameter	Description
data	a parameter

Declaration

public static boolean isNumber(String data) 

Method Source Code

//package com.java2s;
/*/*w w  w .  j av a 2  s .  c o m*/
 *  COMPONENT-GRAPHER v1.0
 *  
 *  Copyright (C) 2015-2016  Etienne Lord
 *
 *  This program is free software: you can redistribute it and/or modify
 *  it under the terms of the GNU General Public License as published by
 *  the Free Software Foundation, either version 3 of the License, or
 *  (at your option) any later version.
 * 
 *  This program is distributed in the hope that it will be useful,
 *  but WITHOUT ANY WARRANTY; without even the implied warranty of
 *  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the 
 *  GNU General Public License for more details.
 *
 *  You should have received a copy of the GNU General Public License
 *  along with this program.  If not, see <http://www.gnu.org/licenses/>.
 */

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static Pattern isNumber = Pattern.compile("[0-9]{1,}(.[0-9]*])*");

    /**
     * Using Regex, find if we have a number in the String
     * @param data
     * @return 
     */
    public static boolean isNumber(String data) {
        Matcher m = isNumber.matcher(data);
        return m.find();
    }
}

Related

1. isNum(String str)
2. isNum(String str)
3. isNumber(String number)
4. isNumber(String s)
5. isNumber(String s)
6. isNumber(String s, boolean[] realnum)