Java Regex Number Validate isNumber(String s)

Here you can find the source of isNumber(String s)

Description

Returns true if input string is numeric and false otherwise

License

Apache License

Parameter

Parameter Description
s the string to test on numeric value

Return

true if the string is a number; false otherwise.

Declaration

public static boolean isNumber(String s) 

Method Source Code

//package com.java2s;
/*//ww  w .ja va2  s  .c om
 * Copyright 2007-2014 Mikhail Khodonov
 *
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not
 * use this file except in compliance with the License. You may obtain a copy of
 * the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
 * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
 * License for the specific language governing permissions and limitations under
 * the License.
 *
 * $Id$
 */

import java.util.regex.Pattern;

public class Main {
    private static Pattern _numPattern = Pattern.compile("-?\\d+(\\.\\d+)?");

    /**
     * Returns true if input string is numeric and false otherwise
     * 
     * @param s
     *            the string to test on numeric value
     * 
     * @return true if the string is a number; false otherwise.
     */
    public static boolean isNumber(String s) {
        return (_numPattern.matcher(s).matches());
    }
}

Related

  1. isNum(String str)
  2. isNum(String str)
  3. isNumber(String data)
  4. isNumber(String number)
  5. isNumber(String s)
  6. isNumber(String s, boolean[] realnum)
  7. isNumber(String str)
  8. isNumber(String str)