Java HTML / XML How to - Extend DefaultHandler and handle SAX errors during parsing

Question

We would like to know how to extend DefaultHandler and handle SAX errors during parsing.

Answer

  // w  w  w  .j a v a2s.  co m
 
import java.io.StringReader;

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.helpers.DefaultHandler;

public class Main {
  public static String getXMLData() {
    return "<x></a>";
  }

  public static void main(String[] argv) throws Exception {
    SAXParserFactory factory = SAXParserFactory.newInstance();
    factory.setValidating(true);
    SAXParser parser = factory.newSAXParser();
    SaxHandler handler = new SaxHandler();
    parser.parse(new InputSource(new StringReader(getXMLData())), handler);
  }
}

class SaxHandler extends DefaultHandler {
  public void startElement(String uri, String localName, String qName,
      Attributes attrs) throws SAXException {
    if (qName.equals("order")) {
    }
  }

  public void error(SAXParseException ex) throws SAXException {
    System.out.println("ERROR: [at " + ex.getLineNumber() + "] " + ex);
  }

  public void fatalError(SAXParseException ex) throws SAXException {
    System.out.println("FATAL_ERROR: [at " + ex.getLineNumber() + "] " + ex);
  }

  public void warning(SAXParseException ex) throws SAXException {
    System.out.println("WARNING: [at " + ex.getLineNumber() + "] " + ex);
  }
}