Java HTML / XML How to - Get features of the SAX parser implementation

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Question

We would like to know how to get features of the SAX parser implementation.

Answer

  /*from   ww w.jav  a  2s  . c  o  m*/

 
import javax.xml.parsers.SAXParserFactory;

public class Main {
  public static void main(String[] argv) throws Exception {
    SAXParserFactory factory = SAXParserFactory.newInstance();
    String features[] = { "http://xml.org/sax/features/namespaces",
        "http://xml.org/sax/features/namespace-prefixes",
        "http://xml.org/sax/features/string-interning", "http://xml.org/sax/features/validation",
        "http://xml.org/sax/features/external-general-entities",
        "http://xml.org/sax/features/external-parameter-entities",
        "http://xml.org/sax/features/lexical-handler/parameter-entities", };
    for (int i = 0; i < features.length; i++) {
      System.out.print("\t- '" + features[i] + "' is ");
      System.out.println("'" + factory.getFeature(features[i]) + "'");
    }
  }
}

The code above generates the following result.

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